If a volume of #1.7*atm# at #26.0*L# is compressed to #10.7*L#, what is the new pressure?

1 Answer
Jun 18, 2017

Answer:

Explanation:

Which holds that for a given mass of gas at constant temperature, then #PV=k#, where #k# is some constant...........and so under equivalent conditions of temperature......

#P_1V_1 = P_2V_2#................

And here we solve for #P_2=(P_1V_1)/V_2#

#=(1.7*atmxx26.0*L)/(10.7*L)#

#=4.1*atm.........#

Why is it reasonable that pressure has increased?