# Question 47e32

Jul 5, 2017
1. $1.75$ $\text{mol Cu}$

2. $26.4$ $\text{g Cu}$

#### Explanation:

1.

We're asked to find how many moles of $\text{Cu}$ are required to react with $3.50$ ${\text{mol AgNO}}_{3}$.

To do this, we can use the coefficients in the chemical equation like this::

3.50cancel("mol AgNO"_3)((1color(white)(l)"mol Cu")/(2cancel("mol AgNO"_3))) = color(red)(1.75 color(red)("mol Cu"

2.

We can solve the second question similar to the first one; we use the molar mass of $\text{Ag}$ ($107.87$ $\text{g/mol}$) to convert from grams to moles:

89.6cancel("g Ag")((1color(white)(l)"mol Ag")/(107.87cancel("g Ag"))) = 0.831 $\text{mol Ag}$

Now use the coefficients of the equation to find the equivalent number of moles of $\text{Cu}$:

0.831cancel("mol Ag")((1color(white)(l)"mol Cu")/(2cancel("mol Ag"))) = 0.415 $\text{mol Cu}$

Lastly, we use the molar mass of copper ($63.55$ $\text{g/mol}$) to convert this to grams:

0.415cancel("mol Cu")((63.55color(white)(l)"g Cu")/(1cancel("mol Cu"))) = color(blue)(26.4 color(blue)("g Cu"#