What would happen if there was no hybridization in #"CH"_4#?

1 Answer

Answer:

The answer would take a #90^@# shape, even more contracted than water.

Explanation:

This structure would not happen because #CH_4#, methane, requires 4 bonds.

The pure #2s^2# electrons would be nonbonding, so they have no ability to form more bonds. Then, the pure #2p# orbitals would only form #:CH_2# (with an empty #2p_z#), not #CH_4#.