What is the volume occupied by a gas that has a #1000*mL# at #396*K# under #2*atm# pressure, that is cooled to #200*K#, and the pressure decreased to #0.5*atm#?

1 Answer
Jul 25, 2017

Answer:

#V_2~=8000*mL# as required........

Explanation:

#(P_1V_1)/T_1=(P_2V_2)/T_2#, for a given quantity of gas according to the combined gas law.....

We solve for #V_2=(P_1V_1T_2)/(P_2T_1)=??*mL#

#(2*atm*1000*mL*396*K)/(0.5*atm*200*K)=??*mL#....

Clearly we get an answer with units of volume as required. Do you agree? And remember #1*L-=1000*mL#.