# What is the volume occupied by a gas that has a 1000*mL at 396*K under 2*atm pressure, that is cooled to 200*K, and the pressure decreased to 0.5*atm?

Jul 25, 2017

${V}_{2} \cong 8000 \cdot m L$ as required........

#### Explanation:

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, for a given quantity of gas according to the combined gas law.....

We solve for V_2=(P_1V_1T_2)/(P_2T_1)=??*mL

(2*atm*1000*mL*396*K)/(0.5*atm*200*K)=??*mL....

Clearly we get an answer with units of volume as required. Do you agree? And remember $1 \cdot L \equiv 1000 \cdot m L$.