Given #93.2%# #"w/w"# #"sulfuric acid"# that has #rho=1.835*g*mL^-1#, how should we dilute this to get a #3*N# solution of #0.50*L# volume...?
A messy problem.......we need a
First off, to settle the insurance issue, when you MAKE dilutions with acid and water YOU ALWAYS ADD ACID to water, and never the reverse. Why not? Because if you spit in acid it spits back; I kid you not.
We (i) determine the molarity of our sulfuric acid, and we want the quotient,
Can you see what I have done with the quotient? The numerator represents the moles of sulfuric acid; the denominator represents the volume of the solution; I get a concentration as required.
Now we wants a
So we require,
And using the conc. acid we need ..............