A #30*L# volume of carbon monoxide is reacted with a #10*L# volume of oxygen gas. How much carbon monoxide remains unreacted?

1 Answer
Jul 30, 2017

Answer:

This question needs a bit of work.......

Explanation:

You have the stoichiometric equation......

#CO(g) + 1/2O_2(g) rarr CO_2(g)#

Under equivalent conditions of temperature and pressure, #Vpropn#, where #n="number of moles"....#

And thus you have #30*L# of carbon monoxide, and LESS than ONE EQUIV of dioxygen, i.e. a #10*L# volume rather than a #15*L# volume. WE assume that the dioxygen reacts quantitatively with #20*L# of #CO# to give #20*L# of #CO_2#, leaving #10*L# #CO# UNREACTED.