# A 30*L volume of carbon monoxide is reacted with a 10*L volume of oxygen gas. How much carbon monoxide remains unreacted?

Jul 30, 2017

This question needs a bit of work.......

#### Explanation:

You have the stoichiometric equation......

$C O \left(g\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow C {O}_{2} \left(g\right)$

Under equivalent conditions of temperature and pressure, $V \propto n$, where $n = \text{number of moles} \ldots .$

And thus you have $30 \cdot L$ of carbon monoxide, and LESS than ONE EQUIV of dioxygen, i.e. a $10 \cdot L$ volume rather than a $15 \cdot L$ volume. WE assume that the dioxygen reacts quantitatively with $20 \cdot L$ of $C O$ to give $20 \cdot L$ of $C {O}_{2}$, leaving $10 \cdot L$ $C O$ UNREACTED.