Question

What is quicklime? And what occurs when a `10*g` mass of this material reacts with the carbon dioxide liberated from the decomposition of `1.80*g` of glucose?

Answer 1

Well, `"quick lime"` is simply `CaO(s)`........and we get a `10*g` mass of `"calcium carbonate........."`

Explanation:

And we look at the 1:1 reaction.......

`CaO(s) + CO_2(g) stackrel("water")rarr CaCO_3(s)` `(i)`

`"Moles of calcium oxide"-=(5.6*g)/(56.08*g*mol^-1)=0.10*mol`

And glucose combusts according to ..........

`C_6H_12O_6(s) + 6O_2(g) rarr6CO_2(g) + 6H_2O(l)` `(ii)`

And thus moles of carbon dioxide liberated......

`(1.80*g)/(180.16*g*mol^-1)xx6-=0.600*mol`

And thus because we have EXCESS carbon dioxide, `CO_2` is the reagent in excess in `(i)`...........

And thus we gets `0.10*mol` `CaCO_3`, which represents a mass of `0.10*molxx100.09*g*mol^-1=10.0*g` `"calcium carbonate"`