What is quicklime? And what occurs when a #10*g# mass of this material reacts with the carbon dioxide liberated from the decomposition of #1.80*g# of glucose?

1 Answer
Aug 3, 2017

Answer:

Well, #"quick lime"# is simply #CaO(s)#........and we get a #10*g# mass of #"calcium carbonate........."#

Explanation:

And we look at the 1:1 reaction.......

#CaO(s) + CO_2(g) stackrel("water")rarr CaCO_3(s)# #(i)#

#"Moles of calcium oxide"-=(5.6*g)/(56.08*g*mol^-1)=0.10*mol#

And glucose combusts according to ..........

#C_6H_12O_6(s) + 6O_2(g) rarr6CO_2(g) + 6H_2O(l)# #(ii)#

And thus moles of carbon dioxide liberated......

#(1.80*g)/(180.16*g*mol^-1)xx6-=0.600*mol#

And thus because we have EXCESS carbon dioxide, #CO_2# is the reagent in excess in #(i)#...........

And thus we gets #0.10*mol# #CaCO_3#, which represents a mass of #0.10*molxx100.09*g*mol^-1=10.0*g# #"calcium carbonate"#