# Question #0006e

Fluoromethane, $\text{CH"_3"F}$
The bond enthalpy, $\Delta {H}^{\circ}$, of the $\text{C-F}$ bond, $\text{485 kJ/mol}$, is greater than the bond enthalpy of the $\text{C-I}$ bond, $\text{240 kJ/mol}$. Bond enthalpy is the amount of energy required to break a bond, so the higher the bond enthalpy, the stronger the bond. The other bond found in both $\text{CH"_3"F}$ and $\text{CH"_3"I}$ (iodomethane), is the $\text{C-H}$ bond, which has an enthalpy of $\text{413 kJ/mol}$. So it is intermediate in strength between the $\text{C-F}$ and $\text{C-I}$ bonds.