Question #ee960

Question

Question #ee960

1 Answer

Impact of this question

1631 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-16T19:04:50

There are eight electrons in the antepenultimate shell of bromine.

Explanation:

Bromine has atomic number 35.

Its electron configuration is ${1s}^{2} l {2s}^{2} {2p}^{6} l {3s}^{2} {3p}^{6} l {4s}^{2} {3d}^{10} {4p}^{5}$ $"1s"^2color(white)(l) "2s"^2 "2p"^6color(white)(l) "3s"^2 "3p"^6color(white)(l) "4s"^2 "3d"^10 "4p"^5$ .

The outermost shell ( ${4s}^{2} {3d}^{10} {4p}^{5}$ $"4s"^2 "3d"^10 "4p"^5$ ) contains 17 electrons.

The penultimate (almost the last) shell ( ${3s}^{2} {3p}^{6}$ $"3s"^2 "3p"^6$ ) contains eight electrons.

The antepenultimate (before the penultimate) shell ( ${2s}^{2} {2p}^{6}$ $"2s"^2 "2p"^6$ ) contains eight electrons.

Science

Math

Humanities

... and beyond

Question #ee960

1 Answer

Explanation:

Related questions

Impact of this question