For which salt are there EQUAL numbers of electrons with respect to the anion, and the cation?

Question

#(i)# #"sodium chloride;"#
#(ii)# #"lithium fluoride;"#
#(iii)# #"potassium bromide;"#
#(iv)# #"rubidium bromide."#

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Answer 1 · 2017-09-13T16:34:58

Well, you have a series of binary PAIRS of ions here....and so I think it is #"option 4"#

And so we gots #Na^+Cl^-#, i.e. 10 electrons associated with the #Na^+# cation, and 18 electrons associated with the #Cl^+# anion.

And for #Li^+F^-#, i.e. 2 electrons associated with the #Li^+# cation, and 10 electrons associated with the #Cl^-# anion.

And for #K^+Br^-#, i.e. 18 electrons associated with the #K^+# cation, and 36 electrons associated with the #Br^-# anion.

And for #Rb^+Br^-#, i.e. 36 electrons associated with the #Rb^+# cation, and 36 electrons associated with the #Br^-# anion.