What mass of sodium metal is required to make a mass of #936*g# sodium chloride?

1 Answer
Sep 29, 2017

Answer:

Approx. #400*g# of metal are required........

Explanation:

We interrogate the redox reaction....

#Na(s) + 1/2Cl_2(g) rarr NaCl(s)#

We gots #(0.568*kg)/(70.90*g*mol^-1)=8.01*mol# with respect to dichlorine....

And we gots #(936*g)/(58.44*g*mol^-1)=16.01*mol# with respect to sodium chloride....

And given the stoichiometry, CLEARLY, we require #16.01*mol# sodium metal.....

...which represents a mass of.....

#16.01*molxx22.99*g*mol^-1~=400*g#