Question

What mass of sodium metal is required to make a mass of `936*g` sodium chloride?

Answer 1

Approx. `400*g` of metal are required........

Explanation:

We interrogate the redox reaction....

`Na(s) + 1/2Cl_2(g) rarr NaCl(s)`

We gots `(0.568*kg)/(70.90*g*mol^-1)=8.01*mol` with respect to dichlorine....

And we gots `(936*g)/(58.44*g*mol^-1)=16.01*mol` with respect to sodium chloride....

And given the stoichiometry, CLEARLY, we require `16.01*mol` sodium metal.....

...which represents a mass of.....

`16.01*molxx22.99*g*mol^-1~=400*g`