# Question #aa745

Nov 4, 2017

$\text{6.0 mL}$

#### Explanation:

Assuming that your goal here is to perform a $1 : 10$ dilution of the sample, then you can say that the ratio that exists between the volume of the diluted solution and the volume of the stock solution must be equal to the dilution factor.

In other words, for any dilution, the dilution factor tells you the ratio between the volume of the diluted solution and the volume of the stock solution.

$\text{DF" = V_"diluted"/V_"stock}$

So in order to perform a $1 : 10$ dilution, you need to have a dilution factor equal to $10$. This implies that you will have

${V}_{\text{diluted" = "DF" * V_"stock}}$

${V}_{\text{diluted" = 10 * "0.60 mL}}$

$\textcolor{\mathrm{da} r k g r e e n}{\underline{\textcolor{b l a c k}{{V}_{\text{diluted" = "6.0 mL}}}}}$

I'll leave the answer rounded to two sig figs

This means that in order to perform this dilution, you need to add enough water to the $\text{0.60-mL}$ sample to get its volume to $\text{6.0 mL}$.