# Question 14c76

Jan 29, 2018

$1 : 31$

#### Explanation:

It's worth knowing that the dilution factor, $\text{DF}$, tells you the ratio that exists between the volume of the diluted solution and the volume of the stock solution.

$\text{DF" = V_"diluted"/V_"stock}$

In your case, the volume of the diluted solution will be equal to

${V}_{\text{diluted" = 15 quad mu"L" + 450 quad mu"L" = 465 quad mu"L}}$

This means that the dilution factor for this dilution is equal to

"DF" = (465 color(red)(cancel(color(black)(mu"L"))))/(15color(red)(cancel(color(black)(mu"L")))) = color(blue)(31)#

Now, an equally important thing to know is that the dilution factor also tells you the ratio that exists between the concentration of the stock solution and the concentration of the diluted solution.

$\text{DF" = c_"stock"/c_"diluted}$

This means that you have

${c}_{\text{diluted" = c_"stock"/"DF}}$

which, in your case, gives you

${c}_{\text{diluted" = c_"stock}} / \textcolor{b l u e}{31}$

So for this dilution, the concentration of the diluted solution will be $\textcolor{b l u e}{31}$ times lower than the concentration of the stock solution, i.e. you p[erformed a $1 : \textcolor{b l u e}{31}$ dilution of the stock solution.