Question #8d3d7

1 Answer
Feb 17, 2018

Answer:

#"60.0 mL"#

Explanation:

The thing to remember about a dilution is that you can express the dilution factor as the ratio that exists between the volume of the diluted solution and the volume of the stock solution

#"DF" = V_"diluted"/V_"stock"#

and as the ratio that exists between the concentration of the stock solution and the concentration of the diluted solution.

#"DF" = c_"stock"/c_"diluted"#

This means that, for any dilution, you have

#"DF" = V_"diluted"/V_"stock" = c_"stock"/c_"diluted"#

In your case, the dilution factor is equal to

#"DF" = (6.00 color(red)(cancel(color(black)("M"))))/(1.00color(red)(cancel(color(black)("M")))) = color(blue)(6)#

This basically means that the concentration of the stock solution is #color(blue)(6)# times higher than the concentration of the diluted solution, which implies that the volume of the stock solution must be #color(blue)(6)# times smaller than the volume of the diluted solution.

#"DF" = V_"diluted"/V_"stock" implies V_"diluted" = "DF" * V_"stock"#

This means that you have

#V_"diluted" = color(blue)(6) * "10.0 mL" = color(darkgreen)(ul(color(black)("60.0 mL")))#

The answer is rounded to three sig figs.