# Question 8d3d7

Feb 17, 2018

$\text{60.0 mL}$

#### Explanation:

The thing to remember about a dilution is that you can express the dilution factor as the ratio that exists between the volume of the diluted solution and the volume of the stock solution

$\text{DF" = V_"diluted"/V_"stock}$

and as the ratio that exists between the concentration of the stock solution and the concentration of the diluted solution.

$\text{DF" = c_"stock"/c_"diluted}$

This means that, for any dilution, you have

$\text{DF" = V_"diluted"/V_"stock" = c_"stock"/c_"diluted}$

In your case, the dilution factor is equal to

"DF" = (6.00 color(red)(cancel(color(black)("M"))))/(1.00color(red)(cancel(color(black)("M")))) = color(blue)(6)

This basically means that the concentration of the stock solution is $\textcolor{b l u e}{6}$ times higher than the concentration of the diluted solution, which implies that the volume of the stock solution must be $\textcolor{b l u e}{6}$ times smaller than the volume of the diluted solution.

$\text{DF" = V_"diluted"/V_"stock" implies V_"diluted" = "DF" * V_"stock}$

This means that you have

V_"diluted" = color(blue)(6) * "10.0 mL" = color(darkgreen)(ul(color(black)("60.0 mL")))#

The answer is rounded to three sig figs.