A #0.100 M# solution of chloroacetic acid (#ClCH_2COOH#) is #11.0%# ionized. Using this information, calculate #[ClCH_2COO^−]# and #[H^+]#?

1 Answer
Dec 7, 2017

Answer:

#[ClCH_2COO^−]=[H^+]=0.011M=0.011molcolor(white)(l)dm^(-3)#

Explanation:

#[ClCH_2COOH]=0.100M#

As #11%# is ionised, the concentration of #ClCH_2COOH# is now #89%# of its original value. #0.1*0.89=0.089M#

Being a weak acid, we shall assume that #[ClCH_2COO^−]=[H^+]#

So, the concentrations for #ClCH_2COO^−# is the same as #H^+#.

The concentration which is ionised is #0.011M#, which is the concentration of the two ions.