A 2300 kg rocket shuts off its engine 494km above earth's surface. Its velocity at burnout is 3000 m/s directly upward. Ignoring air resistance, what maximum height will the rocket reach?

Nov 1, 2017

$530035 \textcolor{w h i t e}{i} m$

Explanation:

$2 a S = {v}^{2} - {u}^{2}$

$\implies S = \frac{{v}^{2} - {u}^{2}}{2 a}$

Plug in the values:

$S = \frac{{0}^{2} - {3000}^{2}}{2 \times 8.49}$

$S = - \frac{9000000}{16.98}$

$S = 530035 \textcolor{w h i t e}{i} m$