What is the distance from the Earth's center to a point in space where the gravitational acceleration due to the Earth is 1/24 of its value at the Earth's surface?
The radius of the Earth is approximately
Gravity obeys an inverse square law, decreasing by the square of the distance from the centre.
So the gravitational acceleration due to the Earth will be
#sqrt(24)*4000 ~~ sqrt(25)*4000 = 5*4000 = 20000#miles.
#20000 * 1.6 = 32000#kilometers.