A 3 kilogram object is acted upon by an impulse having a magnitude of 15 N*s. What is the magnitude of the object's change in momentum due to this impulse?

Nov 13, 2015

$15 k g . m / s$

Explanation:

Newton's 2nd law of motion may also be stated in terms of momentum as follows :
The resultant force acting on an object is directly proportional to the rate of change in momentum brought about.
ie. $\sum \vec{F} = \frac{d \vec{p}}{\mathrm{dt}}$, where $\vec{p} = m \vec{v}$.

Rearranging yields : $\sum \vec{F} \mathrm{dt} = m d \vec{v}$.

Thus impulse ($\sum \vec{F} \mathrm{dt}$) equals change in momentum ($m d \vec{v} = d \vec{p}$)