Question

A `3` kilogram object is acted upon by an impulse having a magnitude of `15` `N*s`. What is the magnitude of the object's change in momentum due to this impulse?

Answer 1

`15 kg.m//s`

Explanation:

Newton's 2nd law of motion may also be stated in terms of momentum as follows :
The resultant force acting on an object is directly proportional to the rate of change in momentum brought about.
ie. `sum vecF= (d vecp)/(dt)`, where `vecp = m vecv`.

Rearranging yields : `sum vecF dt = m d vecv`.

Thus impulse (`sum vecFdt`) equals change in momentum (`m d vec v = d vecp`)