# A .50 M solution of sodium thiosulfate, Na_2S_2O_3, is used to create a more dilute solution. If 250 mL of the concentrated solution is diluted to a volume of 2.5 L, determine the concentration of the new solution?

Th initial solution is diluted 10 fold, thus it is $0.050 \cdot m o l \cdot {L}^{-} 1$ after dilution.
$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$=$ $\frac{0.50 \cdot m o l \cdot {L}^{-} 1 \times 0.250 \cdot L}{2.50 \cdot L}$ $=$ $0.050 \cdot m o l \cdot {L}^{-} 1$ with respect to sodium thiosulate. What is the concentration with respect to sodium ion?