# A charge of 12 C is passing through points A and B on a circuit. If the charge's electric potential changes from 58 J to 42 J, what is the voltage between points A and B?

Feb 21, 2018

See the explanation below

#### Explanation:

Apply the equation

$\text{Energy"(J)}$ $= \text{ Electric potential(V)"xx"Charge (C)}$

The charge is $Q = 12 C$

The change in energy is $\Delta E = 58 - 42 = 16 J$

The voltage is

$U = \frac{\Delta E}{Q} = \frac{16}{12} = 1.33 V$