# A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 32 J to 6 J, what is the voltage between points A and B?

Jul 19, 2017

The voltage is $= 1.625 V$

#### Explanation:

The charge is $Q = 16 C$

The change in the electric potential is

$\Delta E = 32 - 6 = 26 J$

The power is

$P = U I$

and the energy is

$E = U I t$

Also,

$Q = I t$

Therefore,

$\Delta E = U \cdot Q$

The voltage is

$U = \Delta \frac{E}{Q} = \frac{26}{16} = 1.625 V$