Question

A charge of `2 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `17 J` to `5 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=6V`

Explanation:

Apply the equation

`"Energy"(J)"` `= " Electric potential(V)"xx"Charge (C)"`

The charge is `Q=2C`

The change in energy is `DeltaE=17-5=12J`

The voltage is

`U=(DeltaE)/(Q)=12/2=6V`