# A charge of 25 C is passing through points A and B on a circuit. If the charge's electric potential changes from 32 J to 25 J, what is the voltage between points A and B?

Mar 29, 2017

The voltage is $= 0.28 V$

#### Explanation:

The potential difference between the points $A$ and $B$ is $= U$

Voltage =Energy/Charge

$U = \frac{\Delta E}{Q}$

$\Delta E = 32 - 25 = 7 J$

The charge is $Q = 25 C$

$1 V = \frac{1 J}{C}$

$U = \frac{7}{25} = 0.28 V$