# A charge of 25 C is passing through points A and B on a circuit. If the charge's electric potential changes from 25 J to 3 J, what is the voltage between points A and B?

Mar 17, 2017

The voltage is $= 0.88 V$

#### Explanation:

The potential difference between the points $A$ and $B$ is

Voltage =Potential energy difference/Charge

$V = \frac{\Delta E}{Q}$

$\Delta E = 25 - 3 = 22 J$

$Q = 25 C$

$1 V = \frac{1 J}{C}$

$V = \frac{22}{25} = 0.88$Volts