A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 42 J to 27 J, what is the voltage between points A and B?

Feb 22, 2017

The voltage is $= 2.5 V$

Explanation:

Work is done by the electric charge in going from $A$ to $B$

$\Delta W = q \left({V}_{B} - {V}_{A}\right)$

$42 - 27 = 6 \cdot {V}_{A B}$

${V}_{A B} = \frac{15}{6} = \frac{5}{2} = 2.5 V$