# A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J to 21 J, what is the voltage between points A and B?

Oct 10, 2016

Porential or voltage is a measure of energy per unit charge. So the change in energy $\Delta U$ is:
$\Delta U = \Delta V q$
$\implies \Delta V = \frac{\Delta U}{q} = \frac{27 - 21}{6} = 1 V$