Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `39 J` to `6 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=5.5V`

Explanation:

The potential difference between the points `A` and `B` is `=U`

Voltage =Energy/Charge

`U=(DeltaE)/Q`

`DeltaE=39-6=33J`

The charge is `Q=6C`

`1 V=(1J)/C`

`U=33/6=5.5V`