A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential energy changes from 36 J to 15 J, what is the voltage between points A and B?

Jul 22, 2018

The voltage is $= 3.5 V$

Explanation:

The charge is

$Q = I t = 6 C$

The energy is

$W = U I t$

And the change in energy is

$\Delta W = \Delta U \times I t$

$36 - 15 = \Delta U \times 6$

$\Delta U = \frac{21}{6} = 3.5 V$