# A charge of 6 C is passing through points A and B on a circuit. If the charge's electric potential changes from 36 J to 12 J, what is the voltage between points A and B?

Feb 17, 2016

${V}_{A B} = - 8 V$
$\Delta W = q \cdot \left({V}_{B} - {V}_{A}\right)$
${V}_{A B} = {V}_{B} - {V}_{A}$
$12 - 36 = 6 \cdot {V}_{A B}$
$- 24 = 6 \cdot {V}_{A B}$
${V}_{A B} = - \frac{24}{6}$
${V}_{A B} = - 8 V$