A charge of #8 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #36 J# to #6 J#, what is the voltage between points A and B?

2 Answers
Feb 25, 2018

Voltage difference = the change in potential energy/charge

So, we can say as potential energy of charge at #A# is higher than that at #B# , #A# is at higher voltage than #B#,

So,the Voltage difference between them is #(36-6)/8 =3.75 V#

Feb 25, 2018

Answer:

The voltage between A and B is 4V (1s.f.)

Explanation:

The change in energy is #30J# and the charge is #8C#

Using the formula #E=QV#, since voltage is simply the energy gained/lost per coulomb of charge,

#V= 30/8 = 3.75V#