Question

A charge of `8 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `36 J` to `6 J`, what is the voltage between points A and B?

Answer 1

Voltage difference = the change in potential energy/charge

So, we can say as potential energy of charge at `A` is higher than that at `B` , `A` is at higher voltage than `B`,

So,the Voltage difference between them is `(36-6)/8 =3.75 V`

Answer 2

The voltage between A and B is 4V (1s.f.)

Explanation:

The change in energy is `30J` and the charge is `8C`

Using the formula `E=QV`, since voltage is simply the energy gained/lost per coulomb of charge,

`V= 30/8 = 3.75V`