A charge of 8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 36 J to 6 J, what is the voltage between points A and B?

2 Answers
Feb 25, 2018

Voltage difference = the change in potential energy/charge

So, we can say as potential energy of charge at A is higher than that at B , A is at higher voltage than B,

So,the Voltage difference between them is (36-6)/8 =3.75 V

Feb 25, 2018

The voltage between A and B is 4V (1s.f.)

Explanation:

The change in energy is 30J and the charge is 8C

Using the formula E=QV, since voltage is simply the energy gained/lost per coulomb of charge,

V= 30/8 = 3.75V