# A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 15 J to 9 J, what is the voltage between points A and B?

Mar 22, 2016

$667 m V$

#### Explanation:

Voltage or potential difference is defined as the work done per unit charge to move charges between the 2 points.

$\therefore V = \frac{W}{Q}$

$= \frac{15 J - 9 J}{9 C}$

$= 0.667 V$#