# A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 5 J to 2 J, what is the voltage between points A and B?

Sep 19, 2017

$\frac{1}{3} \text{volt}$
$\text{Voltage between A and B} = - \frac{{U}_{B} - {U}_{A}}{q}$
${U}_{A} = 5 J$ and ${U}_{B} = 2 J$
${V}_{A B} = - \frac{{U}_{B} - {U}_{A}}{q}$
${V}_{A B} = - \frac{2 - 5}{9} = \frac{1}{3} \text{Volt}$