# A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 10 J to 5 J, what is the voltage between points A and B?

Mar 8, 2016

#### Answer:

$556 m V$

#### Explanation:

By definition, the voltage (or potential difference) between any 2 points in an electric circuit is the work done per unit charge to move a coulomb of charge between the 2 points.

$\therefore V = \frac{W}{Q}$

$= \frac{10 - 5}{9}$

$= 0.556 V$