Question

A chemist reacted 0.05 moles of solid sodium with water to form hydroxide solution. The chemical reaction for this is: Na + H2O = NaOH + H2. What mass of sodium was reacted?

Answer 1

The stoichiometrically balanced equation for this is.....

`Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr`

Explanation:

Anyway you asked the mass of sodium reacted. This is simply `0.05*molxx22.99*g*mol^-1=1.15*g`.

Can you tell me (i) the volume of dihydrogen gas released given `298*K` temperatures, and `1*atm` pressures; and (ii) the `pH` of the resulting solution had it been diluted to `1*L`?

Enquiring minds want to know!