# A chemist reacted 0.05 moles of solid sodium with water to form hydroxide solution. The chemical reaction for this is: Na + H2O = NaOH + H2. What mass of sodium was reacted?

Jul 9, 2017

The stoichiometrically balanced equation for this is.....

$N a \left(s\right) + {H}_{2} O \left(l\right) \rightarrow N a O H \left(a q\right) + \frac{1}{2} {H}_{2} \left(g\right) \uparrow$

#### Explanation:

Anyway you asked the mass of sodium reacted. This is simply $0.05 \cdot m o l \times 22.99 \cdot g \cdot m o {l}^{-} 1 = 1.15 \cdot g$.

Can you tell me (i) the volume of dihydrogen gas released given $298 \cdot K$ temperatures, and $1 \cdot a t m$ pressures; and (ii) the $p H$ of the resulting solution had it been diluted to $1 \cdot L$?

Enquiring minds want to know!