A chemist reacted 0.05 moles of solid sodium with water to form hydroxide solution. The chemical reaction for this is: Na + H2O = NaOH + H2. What mass of sodium was reacted?

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A chemist reacted 0.05 moles of solid sodium with water to form hydroxide solution. The chemical reaction for this is: Na + H2O = NaOH + H2. What mass of sodium was reacted?

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Answer 1 · 2017-07-09T18:27:24

The stoichiometrically balanced equation for this is.....

$N a (s) + H_{2} O (l) \to N a O H (a q) + \frac{1}{2} H_{2} (g) ↑ ⏐ ⏐ ⏐$ $Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr$

Explanation:

Anyway you asked the mass of sodium reacted. This is simply $0.05 \cdot m o l \times 22.99 \cdot g \cdot m o l^{- 1} = 1.15 \cdot g$ $0.05*molxx22.99*g*mol^-1=1.15*g$ .

Can you tell me (i) the volume of dihydrogen gas released given $298 \cdot K$ $298*K$ temperatures, and $1 \cdot a t m$ $1*atm$ pressures; and (ii) the $p H$ $pH$ of the resulting solution had it been diluted to $1 \cdot L$ $1*L$ ?

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A chemist reacted 0.05 moles of solid sodium with water to form hydroxide solution. The chemical reaction for this is: Na + H2O = NaOH + H2. What mass of sodium was reacted?

1 Answer

Explanation:

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