# A circuit with a resistance of 3 Omega has a fuse with a capacity of 2 A. Can a voltage of 2 V be applied to the circuit without blowing the fuse?

Mar 4, 2018

yes

#### Explanation:

$V = I R$

voltage = current * resistance

here, $R = 3 \Omega$

and $V = 2 V$

$I = \frac{V}{R} = \frac{2 V}{3 \Omega}$

$I = \frac{2}{3} A$

when a voltage of $2 V$ is applied, the current is $\frac{2}{3} A$.

a fuse blows when the current goes beyond a certain level.

if the capacity of the fuse is $2 A$, the fuse will blow at any current higher than $2 A$.

$\frac{2}{3} A < 2 A$

there is not enough current for the fuse to blow.

a voltage of $2 V$ can be applied without blowing the fuse.