A circuit with a resistance of #3 Omega# has a fuse with a capacity of #2 A#. Can a voltage of #2 V# be applied to the circuit without blowing the fuse?

1 Answer
Mar 4, 2018

Answer:

yes

Explanation:

#V = IR#

voltage = current * resistance

here, #R = 3Omega#

and #V = 2V#

#I = V/R = (2V)/(3Omega)#

#I = 2/3A#

when a voltage of #2V# is applied, the current is #2/3A#.

a fuse blows when the current goes beyond a certain level.

if the capacity of the fuse is #2A#, the fuse will blow at any current higher than #2A#.

#2/3 A < 2A#

there is not enough current for the fuse to blow.

a voltage of #2V# can be applied without blowing the fuse.