A circuit with a resistance of #6 Omega# has a fuse melts at #5 A#. Can a voltage of #32 V# be applied to the circuit without blowing the fuse?

1 Answer
Jan 26, 2016

Answer:

#No#

Explanation:

Data:-

Resistance#=R=6Omega#

Voltage#=V=32V#

The fuse has capacity of 5A

Sol:-

If we apply voltage #V# across a resistor whose resistance is #R# then the current #I# flowing across it can be calculated by

#I=V/R#

Here we are applying voltage of #32V# across a #6Omega# resistor, therefore, the current flowing is

#I=32/6=5.333# #implies I=5.333A#

Since, the fuse has capacity of #5A# but the current flowing in the circuit is #5.333A# therefore, the fuse will melt. Thus, the answer to this question is #No#.