A guy drops a rock from a bridge and it hits the river 3.60s later. How high is the bridge?

1 Answer
Nov 14, 2015

Answer:

The formula that will answer this question is
#d = v_i t + 1/2 a t^2 #

Explanation:

The information you have been given:
#v_i# = 0 m/s (the rock was not previously moving)
#t# = 3.60 s
#a = 9.80 m/s^2#, as it is resulting from gravity

Plug these values into your formula. This should give you an answer of 63.50 m.