# A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 14.4 g. What is its density?

$\rho = \text{mass"/"volume} \cong 2.5 \cdot g \cdot c {m}^{-} 3$
rho=(14.4*g)/(5.74*g*cm^-3)=??*g*cm^-3