A model train, with a mass of $2 kg$ , is moving on a circular track with a radius of $4 m$ . If the train's kinetic energy changes from $2 j$ to $96 j$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-03-25T09:35:46

The centripetal force change by $=47N$

The centripetal force is

$F=(mv^2)/r$

The kinetic energy is

$KE=1/2mv^2$

The variation of kinetic energy is

$Delta KE=1/2mv^2-1/2m u^2$

$=1/2m(v^2-u^2)$

The variation of centripetal force is

$DeltaF=m/r(v^2-u^2)$

$DeltaF=2m/r1/2(v^2-u^2)$

$=(2)/r*1/2m(v^2-u^2)$

$=(2)/r*Delta KE$

$=2/4*(96-2)N$

$=47N$

A model train, with a mass of 2 kg2 kg, is moving on a circular track with a radius of 4 m4 m. If the train's kinetic energy changes from 2 j2 j to 96 j96 j, by how much will the centripetal force applied by the tracks change by?