A model train, with a mass of #4 kg#, is moving on a circular track with a radius of #8 m#. If the train's kinetic energy changes from #4 j# to #15 j#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 24, 2017

Answer:

The centripetal force change by #=2.75N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The kinetic energy is

#KE=1/2mv^2#

The variation of kinetic energy is

#Delta KE=1/2mv^2-1/2m u^2#

#=1/2m(v^2-u^2)#

The variation of centripetal force is

#DeltaF=m/r(v^2-u^2)#

#DeltaF=2m/r1/2(v^2-u^2)#

#=(2)/r*1/2m(v^2-u^2)#

#=(2)/r*Delta KE#

#=2/8*(15-4)N#

#=11/4N#

#=2.75N#