A model train, with a mass of #5 kg#, is moving on a circular track with a radius of #9 m#. If the train's kinetic energy changes from #25 j# to #40 j#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 23, 2017

Answer:

The change in centripetal force is #=3.33N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The kinetic energy is

#KE=1/2mv^2#

The variation of kinetic energy is

#Delta KE=1/2mv^2-1/2m u^2#

#=1/2m(v^2-u^2)#

The variation of centripetal force is

#DeltaF=m/r(v^2-u^2)#

#=2/r*1/2m(v^2-u^2)#

#=2/r*Delta KE#

#=2/9*(40-25)N#

#=2/9*15N#

#=3.33N#