A model train, with a mass of $5 k g$ $5 kg$ , is moving on a circular track with a radius of $3 m$ $3 m$ . If the train's rate of revolution changes from $\frac{1}{3} H z$ $1/3 Hz$ to $\frac{2}{7} H z$ $2/7 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-04-14T12:04:42

The change in centripetal force $= 1.34 N$ $=1.34N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

mass is $m = 5 k g$ $m=5kg$

radius $r = 3 m$ $r=3m$

$Delta omega=(1/3-2/7)*2pi=(2/21pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=5*3*(2/21pi)^2$

$=1.34N$

A model train, with a mass of 5 kg5kg5 kg, is moving on a circular track with a radius of 3 m3m3 m. If the train's rate of revolution changes from 1/3 Hz13Hz1/3 Hz to 2/7 Hz27Hz2/7 Hz, by how much will the centripetal force applied by the tracks change by?