A model train with a mass of #8 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #48 cm# to #240 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 11, 2017

Answer:

The change in centripetal force is #=0.192N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=8kg#

#v=0.12ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=8*0.12^2/0.48=0.24N#

#F_2=8*0.12^2/2.40=0.048N#

#DeltaF=0.24-0.048=0.192N#