A model train, with a mass of #8 kg#, is moving on a circular track with a radius of #8 m#. If the train's kinetic energy changes from #32 j# to #0 j#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 25, 2017

Answer:

The change in centripetal force is #=8N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The kinetic energy is

#KE=1/2mv^2#

The variation of kinetic energy is

#Delta KE=1/2mv^2-1/2m u^2#

#=1/2m(v^2-u^2)#

The variation of centripetal force is

#DeltaF=m/r(v^2-u^2)#

#DeltaF=2m/r1/2(v^2-u^2)#

#=(2)/r*1/2m(v^2-u^2)#

#=(2)/r*Delta KE#

#=2/8*(32-0)N#

#=8N#