A parallelogram has sides A, B, C, and D. Sides A and B have a length of #2 # and sides C and D have a length of # 8 #. If the angle between sides A and C is #(3 pi)/4 #, what is the area of the parallelogram?

Question

910 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-11T12:37:15

Area of the parallelogram is #11.3136#.

Area of a parallelogram whose unequal sides are #a# and #b# and angle between them is #theta# is given by #axxbxxsintheta#.

As the given parallelogram has sides #2# and #8# and angle between them is #3pi/4#

the area of the parallelogram is #2xx8xxsin((3pi)/4)#

or #2xx8xx0.7071=11.3136#