A parallelogram has sides A, B, C, and D. Sides A and B have a length of #3 # and sides C and D have a length of # 8 #. If the angle between sides A and C is #(7 pi)/18 #, what is the area of the parallelogram?

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Answer 1 · 2016-03-11T12:25:52

The area of the parallelogram is #9.1848#.

Area of a parallelogram whose unequal sides are #a# and #b# and angle between them is #theta# is given by #axxbxxsintheta#.

As the given parallelogram has sides #3# and #8# and angle between them is #7pi/8#

the area of the parallelogram is #3xx8xxsin((7pi)/8)#

or #3xx8xx0.3827=9.1848#