A parallelogram has sides A, B, C, and D. Sides A and B have a length of #5 # and sides C and D have a length of # 8 #. If the angle between sides A and C is #(3 pi)/8 #, what is the area of the parallelogram?

Question

1154 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-11T12:42:43

Area of the parallelogram is #36.956#.

Area of a parallelogram whose unequal sides are #a# and #b# and angle between them is #theta# is given by #axxbxxsintheta#.

As the given parallelogram has sides #5# and #8# and angle between them is #3pi/8#

the area of the parallelogram is #5xx8xxsin((3pi)/8)#

or #5xx8xx0.9239=36.956#