A projectile is shot from the ground at a velocity of #1 m/s# and at an angle of #(5pi)/6#. How long will it take for the projectile to land?

1 Answer
Jan 3, 2016

Answer:

#T=0.10204s#

Explanation:

Data:-
Velocity#=V=1m/s#
Angle#=theta=(5pi)/6#
Time of flight #=T=??#
Sol:-
Time of flight is given by#=(2V_(0y))/g#
where #V_(0y)# is the y-component of velocity and #g# is acceleration due to gravity whose value is (9.8 m/s^2).

Y-component of velocity#=V_(0y)=Vsintheta=1*sin((5pi)/6)=0.5#

#T=(2V_(0y))/g=(2*0.5)/9.8=1/9.8=0.1020s#

#implies T=0.10204s#