A projectile is shot from the ground at a velocity of 11 m/s at an angle of pi/6. How long will it take for the projectile to land?

Feb 5, 2016

${x}_{m} = \textcolor{red}{6 , 5} . \textcolor{g r e e n}{1 , 942} = 12 , 623 m$

Explanation:

${v}_{i x} = {v}_{i} . \cos \theta$
${v}_{i x} = 11. \cos \left(\frac{\cancel{\pi}}{6} \cdot \frac{180}{\cancel{\pi}}\right)$
${v}_{i x} = 11. \cos 60$
${v}_{i x} = 11.0 , 5 = 6 , 5 \frac{m}{s}$
$\textcolor{red}{{v}_{i x} = 6 , 5 \frac{m}{s} \text{ initial velocity x component}}$

${t}_{e} = \frac{2. {v}_{i} \sin \theta}{g}$
${t}_{e} = \frac{2.11 . \sin 60}{g}$
${t}_{e} = \frac{22. 0 , 866}{9 , 81}$
$\textcolor{g r e e n}{{t}_{e} = 1 , 942 s \text{ elapsed time}}$
${x}_{m} = {v}_{i x} . {t}_{e}$
${x}_{m} = \textcolor{red}{6 , 5} . \textcolor{g r e e n}{1 , 942} = 12 , 623 m$