A projectile is shot from the ground at a velocity of #11 m/s# at an angle of #pi/6#. How long will it take for the projectile to land?

1 Answer
Feb 5, 2016

Answer:

#x_m=color(red)(6,5). color(green)(1,942)=12,623 m#

Explanation:

#v_(ix)=v_i. cos theta#
#v_(ix)=11. cos (cancel(pi)/6 *180/cancel(pi))#
#v_(ix)=11. cos 60#
#v_(ix)=11.0,5=6,5 m/s#
#color(red)(v_(ix)=6,5 m/s" initial velocity x component")#

#t_e=(2.v_i sin theta)/g#
#t_e=(2.11.sin 60)/g#
#t_e=(22. 0,866)/(9,81)#
#color(green)(t_e=1,942 s" elapsed time")#
#x_m=v_(ix). t_e#
#x_m=color(red)(6,5). color(green)(1,942)=12,623 m#