A projectile is shot from the ground at a velocity of #2 m/s# and at an angle of #(7pi)/12#. How long will it take for the projectile to land?

1 Answer
Jan 11, 2018

Answer:

0.4 sec

Explanation:

Throwing a projectile at an angle #7(pi/12)# means it has been thrown at an angle of #5(pi/12)# w.r.t to the horizontal on to the opposite direction.
Hence,time taken by the projectile to ascend upto its highest point can be calculated using #v=u+at# (all symbols are bearing their conventional meaning)
Here,#v=0# , u=#2 sin 5(pi/12)# ,#a=-g#
So,t=0.2 sec
It will take the same amount of time to get down.
Hence total time to land will be #(2*0.2)# sec or 0.4 sec